Check answers to selected homework problems from the text and for Linear Programming notes
preference. b) Yes. 1/4 to each blend. The classical method of equally likely outcomes. c) 0.20, 0.30, 0.35, 0.15
4. a) 0.604 b) 0.093 c) 0.78 d) 85.8 e) $1.529
6. a) 0.31 b) 0.69
7. a) 0.4, 0.4, 0.6 b) 0.8. Yes c) P(Ac) = 0.6 P(Cc) = 0.4
d) P(AÇBc) = 0.6 e) 0.8
9. 0.72
11. a) Yes. 0.8 b) 0.65
12. a) 0.667 b) 0.8 c) No
13. a) Example-P(FÇQ) = 0.218 b) A student will most likely indicate cost
or convenience as the first reason with a 0.511 probability. c) 0.473
d) 0.386 e) The events are dependent.
15. a) Example-P(18to34ÇYes) = 0.375 b) Example-46% are ages 18 to 34
c) 0.15 d) 0.185 e) 0.120 f) 0.567 g) Probability of no health
insurance coverage is 0.15. A higher probability exists for the younger
group:
approximately 18.5% of the age group. For the 35 and over group it is approximately 12%. Of the no insurance group, more are in
the 18 to 34 age group: approximately 57%.
18. a) 0.25, 0.40, 0.10 b) 0.25 c) The program does not help. Independent
19. a) 0.009 b) 0.101
21. a) 0.50 b) 0.75 c) 0.652
23. a) 0.70 b) The revised probabilities are 0.3125,
0.50, and 0.1875. Probabilities now favor medium-quality oil rather than
high-quality oil.
0.8125
24. 0.359
4. a) 6 b) 4.5 c) 2.121
7. a) 445 b) –1,250 c) 9475 97.34
8. a) 145 and 140. Medium b) 2725 and 12,400. Medium
21. a) 0.2967 b) 0.4418 c) 0.33 d) 0.5910 e) 0.8849 f) 0.2389
23. a) - 0.80 b) 1.66 c) 0.26 d) 2.56 e) - 0.5
24. a) 0.3830 b) 0.1056 c) 0.0062 d) 0.1587
25. a) 0.1112 b) 0.1112 c) 40.496
26. a) 0.7745 b) 36.32 c) Approximately 19%
27. a) 0.0475 b) 0.0099 c) 0.7938 d) 796.75
c) Optimistic-d1 Conservative-d2, d3 Minimax regret-d2
6. a) Pharmaceuticals, 3.4% b) Financial, 4.6%
9. a) The decision is the choice of the service type, the chance event is the level
of demand, and the consequence is the amount of quarterly profit.
Two decision alternatives-full price and discount service
Two outcomes for the chance event-strong demand and weak demand
b) Optimistic-full price service Conservative-discount service
Minimax regret-discount service
c) Discount service d) Full price service
13. a) The decision is the choice of the type of grape, the chance event is the
demand for the wine, and the consequence is the expected annual profit
contribution.
Three decision alternatives-plant Chardonnay, plant Riesling, and plant both
Four chance outcomes-week demand for Chardonnay and week
demand for Riesling (WW), and the rest are,WS, SW, and SS
c) Plant Chardonnay grapes only
d) Plant both grapes
14. a) If s1 then d1, if s2 then d1 or d2, if s3 then d2 b) 192.5 c) d1.
182.5 d) 10
16. The optimal decision strategy will depend on the cost of the market research.
17. a) Start the R&D project , and if it successful, build the facility, $10 million
b) $25 million or more
19. b) Sell. $100,000 c) $25,000 d) If favorable, produce, if unfavorable,
sell e) $1035 f) No. $1035 g) No agency, sell the pilot
21. a) Purchase, $200,000 b) If high resistance, do not purchase, if low
resistance purchase c) Yes, $30,400 > $10,000. $30,400
24. a) P(C) = 0.695 P(O) = 0.215 P(R) =0.09
P(S1|C) = 0.978 P(S1|O) = 0.791 P(S1|R) = 0
P(S2|C) = 0.022 P(S2|O) = 0.209 P(S2|R) = 1
c) Check the weather, take the expressway unless there is rain. If rain, Queen
City Avenue. Expected time 26.655 minutes
25. b) EVPI = $9000 c) 0.355 d) Conduct the study if the cost is less
than $3650. If it indicates a favorable condition, manufacture the component.
e) $3650 f) 40.6%
12. a) A = 3, B = 1.5 b) A = 0, B = 3 c) (0,0), (4,0), (3,1.5), and (0,3)
20. b) A = 3.429, B = 3.429, and Max z = 17.145 c) s1 = 2.858, s2 = 0,
s3 = 1.429, s4 = 0
26. x1 = 666.667, x2 = 333.333 and Max z = 60,000
33. a) A = 3, B = 1 and Min z = 5 b) s1 = 14 (slack), s2 = 0 (surplus),
s3 = 10.5 (slack), s4= 0 (surplus) c) A = 6, B = 2, and Max z = 34
39. a) x1 = 4000, x2 = 10,000 b) 60,000 c) Everything should be
invested in the stock fund.
40. x1 = 30, x2 = 25, and Min z = 55
52. x1 = 384, x2 = 80
53. x1 = 50 hours, x2 = 30 hours
Linear Programming: Sensitivity Analysis and Interpretation of Solution Using Excel Solver
1. a) U = 800 H = 1200 $8400 b) 1 and 2. All funds have been invested
and the maximum allowable risk has been reached c) 0.09, 1.33, 0.
For example, increasing the available funds by $1, will increase the annual
return by $0.09 d) No, optimal solution has only 800 shares of U.S. Oil
Stock
2. a) More than $7 b) More than $3.5 c) None
3. a) S = 4000 M =
10,000 62,000 b)
Surplus. Investment in money market funds exceeds the minimum requirement by $7000.
c) For S--
3.75
to No Upper Limit, for M--No
Lower Limit to 6.4 d) $60,000 e) 5%
f) -0.057 risk units. A one-dollar
increase in the available funds will
reduce the total risk by 0.057, a one-dollar decrease in the available funds
will increase the total risk by 0.057 units.
g) 5.7% h) The optimal solution does not change. 67,000
4. a) x1 = 7.297 x2 = 0.000 x3 = 1.892 139.730 b) 2 and 3 c) 0.000,
3.405, 4.432. No improvement can be made by increasing the RHS’s
d) 3. From 20 to 19
5. a) A = 1000 C = 200 H = 0 b) 2 and 4 c) Constraints 1-3 slack,
for example, 4000 minutes of unused cutting and dying time. Constraint 4
surplus. Only the minimum number of All-Pro model is produced.
d) Yes. 0.20 < 0.33 e) -2. An increase of one unit in the requirement will
cause a $2 decrease in profit contribution f) Does not change. $4200
6. a) x1 = 25 x2 = 0 x3 = 25 $1250 b) MI--31.25 hours MII--37.5
hours c) 12.5 d) Yes. x1 = 24 x2 = 8 x3 = 16 $1440
Total audience = 1,052,000 b) 5,130
3. x1 = $630,000 x2 = $170,000 x3 = $460,000 x4 = $140,000 x5 = $600,000
Annual return = $188,800
4. a) x1
= 500 x2
= 300 x3 = 200 b)
$0.55
c) Surplus for aroma, s1 = 0,
therefore aroma rating = 75. Surplus for
taste,
s2 = 4400, therefore taste rating = 80 + 4400/1000 = 84.4 d) $0.60
5. x1 = 4 x2 = 4 x3 = 2
8. x1 = 3 x2 = 3 x3 = 7 x4 = 0 x5 = 4 x6 = 2
11. x11 = 600 x12 = 400 x13 = 0 x21 = 0 x22 = 0 x31 = 800
Total cost = $20,400
13. Contribution to profit = $3233.75
15. x11 = gallons of crude 1 used to produce regular = 266,667 x12 = gallons of
crude 1 used to produce high-octane = 333,333 x21 = gallons of crude 2 used
to produce regular = 533,333 x22 = gallons of crude 2 used to produce high-
octane = 166,667
17. a) FM = 5000 FP = 0 SM = 2692 SP = 7308 StM = 0 StP = 5000
b) Total cost = $368,076.91 c) C--350 hours, M--259.62 hours, and
S--375 hours
d) Nothing e) Yes. For a purchase price below $47.423, the solution
improves
18. a) x1 = 5 x2 = 2 x3 = 3 b) x1 = 7.333 x2 = 0 x3 = 0
Ch.10 3. b) Total cost = $24,800
5. c) Total cost = $11,900 d) With Southern Gas for the additional 100 units.
7. b) Total billing = $57,925 c) New Total Billing = $57,525
8. Total profit = $282,000
9. Total cost = $37,810
10. Total cost = $3990
12. b) Total time = 64 days
13. b) Considering Burton has saved 2 days. c) Ellis
16. Total profit = $61,000
19. Total time = 590 hrs
Ch.12 4. a) A-D-G b) No, the critical path activities require 15 months
to complete
8. b) B, C, E, F, H d) Yes. Project completion time is 49 weeks.
12. a) A, D, H, I b) 25.666 days c) 0.2578
15. c) A, B, G, H, I. 15 weeks d) T = 17.393 weeks
24. c) A, B, C, F 31 weeks f) $112,500
Ch.13 4. a) 1095.445 b) 240 c) 22.822 days d) Holding cost = $273.861,
Ordering cost = $273.861
8. Approximately 12, 5 classes per year, $225,200
10. 1414.214, 28.284 days, 7.071 days
11. a) 1788.854 b) 1333.333 c) 894.427 d) 826.898 EOQ--Q* = 800
1) Q* for Production Lot Size is always greater than the EOQ Q* for the same
D, Co, and Ch values. 2) As P increases, Q* decreases, but remains greater
than the EOQ Q*.
13. a) 1078.119 b) 6.678 c) 37.435 d) 10.781 e) 767.621
f) 2003.49 g) 432
15. a) 1148.913 b) 104.447 c) 1044.466 d) 23.936 e) $522.224
16. 240, r = dm - S, r = 240 - 104.447 = 135.553. The reorder point will be
smaller if backorders are allowed.
20. 100 units.